random 1/4 mile question?
July-8th-2005, 06:01 PM
#1
La Familia!
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Join Date: Oct 2002
Location: La Dee Da Land
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random 1/4 mile question?
ok i had this thought the other day my brother and a friend of ours went to this abandon street that us and alot of the local guys sometimes race at,
and they painted a starting line and a line thats a qtr of a mile away
i ran thru it by my self yesterday and this is where the question comes into play i had no stop clock so what i did was divided my speed 75mph by the number of feet in a 1/4 mile which is 1320 i belive? anyway i came up with 18.02 and some other numbers my question is is this a reasonable way to kinda generically figure out how fast you made it thru the 1/4?
now i didn't launch i just kinda accerated hard but my brother took his mx6 thru and got to like 85 or so which when divided by the feet in a 1/4 mile came out to 15 something which sounds close to what these cars run in a 1/4 mile so what do you think?
peace
dante
and they painted a starting line and a line thats a qtr of a mile away
i ran thru it by my self yesterday and this is where the question comes into play i had no stop clock so what i did was divided my speed 75mph by the number of feet in a 1/4 mile which is 1320 i belive? anyway i came up with 18.02 and some other numbers my question is is this a reasonable way to kinda generically figure out how fast you made it thru the 1/4?
now i didn't launch i just kinda accerated hard but my brother took his mx6 thru and got to like 85 or so which when divided by the feet in a 1/4 mile came out to 15 something which sounds close to what these cars run in a 1/4 mile so what do you think?
peace
dante
July-9th-2005, 07:39 AM
#5
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Join Date: Feb 2005
Location: Melbourne Australia
Posts: 345
u could a lways try the motion in a straight line formulas... wont be the most accurate but yeh hehe..
U(initial speed), V(final speed), A(acceleration), S(distance), T(time)... i caint remember the 4 formulas off the top of my head
V = U + AT.... i know is one...
V^2 = U^2 + 2AS
oh man its late and i caint find my physics notes LOL... i will get back to ya;ll later if it still aint solved...
U(initial speed), V(final speed), A(acceleration), S(distance), T(time)... i caint remember the 4 formulas off the top of my head
V = U + AT.... i know is one...
V^2 = U^2 + 2AS
oh man its late and i caint find my physics notes LOL... i will get back to ya;ll later if it still aint solved...
July-9th-2005, 08:10 AM
#6
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Join Date: Jan 2004
Location: Pittsburgh PA
Posts: 3,186
Originally Posted by MC
u could a lways try the motion in a straight line formulas... wont be the most accurate but yeh hehe..
U(initial speed), V(final speed), A(acceleration), S(distance), T(time)... i caint remember the 4 formulas off the top of my head
V = U + AT.... i know is one...
V^2 = U^2 + 2AS
oh man its late and i caint find my physics notes LOL... i will get back to ya;ll later if it still aint solved...
U(initial speed), V(final speed), A(acceleration), S(distance), T(time)... i caint remember the 4 formulas off the top of my head
V = U + AT.... i know is one...
V^2 = U^2 + 2AS
oh man its late and i caint find my physics notes LOL... i will get back to ya;ll later if it still aint solved...
Here's my solution: go to Kmart or something and buy a cheap stopwatch. It's more accurate than looking at your speedo when you cross the line.
July-10th-2005, 06:35 AM
#7
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Join Date: Feb 2005
Location: Melbourne Australia
Posts: 345
also keep into account that formulas only work for constant acceleration... and it wont take into account wind resistance, and other frictional forces involved...
as kargoboy stated... buy a stop watch hehe.... or even spend like $50 and buy the old skool Gtech.... does it all for ya.... and a bit more
as kargoboy stated... buy a stop watch hehe.... or even spend like $50 and buy the old skool Gtech.... does it all for ya.... and a bit more
July-10th-2005, 09:35 AM
#8
La Familia!
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Location: La Dee Da Land
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Yeah, but you are on the right track (no pun intended). I always sucked at math but I know you need to account for acceleration and the fact that you are starting from a stopped (non-intertial) position.
Here's my solution: go to Kmart or something and buy a cheap stopwatch. It's more accurate than looking at your speedo when you cross the line.
Here's my solution: go to Kmart or something and buy a cheap stopwatch. It's more accurate than looking at your speedo when you cross the line.
also keep into account that formulas only work for constant acceleration... and it wont take into account wind resistance, and other frictional forces involved...
as kargoboy stated... buy a stop watch hehe.... or even spend like $50 and buy the old skool Gtech.... does it all for ya.... and a bit more
as kargoboy stated... buy a stop watch hehe.... or even spend like $50 and buy the old skool Gtech.... does it all for ya.... and a bit more
i'll post the results if i do
peace
dante
July-10th-2005, 10:35 PM
#9
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Join Date: Jul 2004
Location: Austin, Tx
Posts: 1,099
Originally Posted by kargoboy
Yeah, but you are on the right track (no pun intended). I always sucked at math but I know you need to account for acceleration and the fact that you are starting from a stopped (non-intertial) position.
Here's my solution: go to Kmart or something and buy a cheap stopwatch. It's more accurate than looking at your speedo when you cross the line.
Here's my solution: go to Kmart or something and buy a cheap stopwatch. It's more accurate than looking at your speedo when you cross the line.
For some reason this was really funny to me, made me spit my drink out. Thanks
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